Physics, asked by moffatkikwepe, 9 months ago

What is the power dissipated when a voltage of 400V is applied across a 120k ohm resistor?

Answers

Answered by djagan72

5

P=V^2/r

= (400)^2/120

=160000/120

=4000/3

=1333.33w. (approximately).

therefore, the power drawn is 1333.33 w

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