What is the power dissipitation in an ac circuit in which voltage and current are given by V=300sin(wt-pi/2) and I=10sin(wt)
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V(max)=300V
I(max)=10A
Vrms=V(max)/2^=300/2^=212.1340V
Irms=I(max)/2^=10/2^=7.071A
P=Vrms*Irms
= 212.1340*7.071
= 1500.03Watt
I(max)=10A
Vrms=V(max)/2^=300/2^=212.1340V
Irms=I(max)/2^=10/2^=7.071A
P=Vrms*Irms
= 212.1340*7.071
= 1500.03Watt
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