What is the power in horsepower of a DC motor operating at 1000 RPM and 2 lb-ft torque? (Type in a two-decimal number.)
Answers
Answer:
Torque (lb.in) = 63,025 x Power (HP) / Speed (RPM)
Power (HP) = Torque (lb.in) x Speed (RPM) / 63,025.
Torque (N.m) = 9.5488 x Power (kW) / Speed (RPM)
Power (kW) = Torque (N.m) x Speed (RPM) / 9.5488.
Explanation:
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Answer:
Torque (lb. in) = 63,025 x Power (HP) / Speed (RPM)
Power (HP) = Torque (lb. in) x Speed (RPM) / 63,025.
Torque (N.m) = 9.5488 x Power (kW) / Speed (RPM)
Power (kW) = Torque (N.m) x Speed (RPM) / 9.5488.
Explanation:
Calculator for Electric Motor Horsepower
James Watt, a Scottish engineer, used the term "horsepower" in the 18th century to contrast the output of steam engines with the strength of horses. Since then, the phrase has been used to refer to the power output in various systems, such as electric motors.
However, there are a few aspects that every engineer has to be aware of when calculating the horsepower of an electric motor. Design calculations for electric motor horsepower are covered in this article. It also includes estimates for full load amperage rating and motor efficiency.
Conclusion
Although this article offers useful advice on calculating the horsepower of electric motors, there are still a number of factors that an engineer must take into account when selecting electric motors. For instance, engineers still have to choose the right winding size, take into account the operational environment, and prepare for the power supply. Therefore, it is suggested that engineers get in touch with electric motor suppliers to talk about their application needs.
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