Question

what is the power of a concave lens required to correct the vision of a person's eye whose far point is 50 cm ?​

Answer 1

Answer:

0.2

Explanation:

f=1/power

:p=1/0.5=0.2

Answer 2

The power of a concave lens is 2 D.

Explanation:

Given that,

The far point of the person's eye, v = 50 cm

The object is placed at a distance of infinite, $u=-\infty$

We need to find the power of a concave lens. It can be calculated using lens formula as :

$\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}$

$\dfrac{1}{f}=\dfrac{1}{50}-\dfrac{1}{-\infty}$

f = 50 cm

Power, P = 1/f

$P=\dfrac{1}{50}$

$P=0.02\ m^{-1}$

or

P = 2 D

So, the power of a concave lens is 2 D. Hence, this is the required solution.

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Lens formula

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