What is the power of a machinethat can lift a load of 750N through 15m in 5 sec? What must have been the effort applied? Obtain the M.A. and V.R. of this machine. Assume the machine to be an ideal one and take the distance moved by the effort as 45m.
Answers
Answered by
1
MA =(dE/dl)
=(45/15)
=3
VR=MA=3 (for an ideal machine)
therefore efficiency=1
work output=work input
p=(F×S)/t
=(750×15)/5
=2250watt
Therefore the required power is 2250W
can lift a load of 750N.
=(45/15)
=3
VR=MA=3 (for an ideal machine)
therefore efficiency=1
work output=work input
p=(F×S)/t
=(750×15)/5
=2250watt
Therefore the required power is 2250W
can lift a load of 750N.
koushik18:
pleasssss mark it as brainliest
Similar questions