Question

what is the power of convex lens of focal length is +0.3.​

Answer 1

Answer:

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5On applying Lensmaker formula , we have

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5On applying Lensmaker formula , we have∴1f=(μ−1)(1R1−1R2)⇒130=(1.5−1)(1∞−1R2)

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5On applying Lensmaker formula , we have∴1f=(μ−1)(1R1−1R2)⇒130=(1.5−1)(1∞−1R2)⇒130=0.5(−1R2)⇒R2=−0.5×30=−15cm

Her f=0.3Ωm=30cm,R1=∞( for plane surface ),R2=?,μ=1.5On applying Lensmaker formula , we have∴1f=(μ−1)(1R1−1R2)⇒130=(1.5−1)(1∞−1R2)⇒130=0.5(−1R2)⇒R2=−0.5×30=−15cm∴ Radius of curved surface =15 cm.

Answer 2

Thus, a diverging lens having a focal length of 1 m has a power of -1 diopter, and a converging lens of focal length 0.3 m has a power of two diopters.