Question

What is the power out of U™ reactor, if it takes 30 days to use 2 kg of fuel and if each fission gives 185 MeV of
unusable energy?​

Answer 1

Answer:

$mass \: of \: u \: per \: second \: in \: reactor \: is$

$m = \frac{2 \times {10}3{} }{30 \times 24 \times 60 \times 60}$

$m = 7.72 \times {10}^ - 4{} g {sec}^ - 1{}$

$therefore \: no.of \: fissions \: reaction \: per \: second$

$= \frac{6 \times {10}^23{} }{235} \times m$

$= \frac{6 \times {10}^23{} \times 7.72 \times {10}^ - 4{} }{235}$

$= 1.97 \times {10}^18{}$

power of nuclear reactor

$= 58.3mw$

Explanation:

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- Tanvi

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