Question

What is the power rating (in W) of a bulb if a current of 0.3 A passes through on application of 240 V of potential difference across its terminals?
A) 800 B) 36 C) 400 D) 72

Answer 1

Answer:

sorry but i not understand this question

Answer 2

Given:
I= .3A
P.D= 240V

To find:
P=?

Answer: D)72

Explanation:

P=V^2/R
V=IR (Ohm’s Law)

R=V/I=240V/0.3A
=800 ohms

P=240^2/800=72W

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