Question

what is the pressure acting on a rectangular Board of length 50 M and width 30M when acted upon by a force of 50000 N. Answer fast please​

Answer 1

Answer:

$\bf { 3.\overline{3} \; Pa }$

Explanation:

As per the provided information in the given question, we have :

• Length of the rectangular board = 50 m
• Width of the rectangular board = 30 m
• Force applied (F) = 50000 N

We are asked to calculate the pressure acting on the rectangular board.

Firstly, let's understand about pressure. Pressure is defined as force per unit area. Its SI unit is Pascal. Pascal is denoted by Pa. Pa is equivalent to N/m². When area is less, pressure exerted is more. When area is more, pressure exerted is less. When force applied is more, pressure exerted is more.

Now, as we know that,

$\longmapsto \bf { P = \dfrac{F}{A} }$

• P denotes pressure
• F denotes force
• A denotes area

Here, we need to find the area first. We can write Length × Breadth at the place of Area because area of rectangle is equivalent to the product of its length and breadth.

$\longmapsto \rm { P = \dfrac{50000 \; N}{50 \; m \times 30 \; m} }$

$\longmapsto \rm { P = \dfrac{50000 \; N}{1500 \; m^2} }$

Cancelling the zeroes.

$\longmapsto \rm { P = \dfrac{500 \; N}{15 \; m^2} }$

$\longmapsto \rm { P = \dfrac{100 \; N}{3 \; m^2} }$

$\longmapsto \rm { P = 3.\overline{3} \; N.m^{-2} }$

$\longmapsto \bf { P = 3.\overline{3} \; Pa }$

∴ Pressure acting on the board is $\bf { 3.\overline{3} \; Pa }$.