What is the pressure and thrust on the bottom of the cylindrical vessel of diameter 28cm containing 30.8 gram of Mercury?(density of mercury = 13.6g/cc)
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Given :
Diameter of the cylinder = 28 cm
Mass of mercury = 30.8 g
Density of mercury = 13.66 g/cc
To Find :
The pressure and thrust on the bottom of the vessel
Solution :
- Pressure at the bottom of the tank is given by
P = ρgh
P = 13.6 × 9.8 × 28
P = 3731.84 dyne-cm⁻²
- Surface area at the bottom of the tank = π(r)² = π(28)² = 2463 cm²
- The thrust acting at the bottom of the tank is
Thrust = Force × Area
Thrust = 3731.84 × 2463
Thrust = 92.02 N
The pressure at the bottom of the tank is 3731.84 dyne-cm⁻².
The thrust on the bottom of the tank is 92.02 N.
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ans in the first person ok
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