what is the pressure at 50m under sea ? R.D.of sea water is 1.03 and g = 9.8 m/s . plz help me tmorow is my submitin .
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Answered by
2
given ,
g = 9.8m/s
h = 50 m
Pressure = hdg
density = 1.03 * 10^3 kg/m^2
P = 50 * 1.03 * 10^3 * 9.8 N/m^2
=
g = 9.8m/s
h = 50 m
Pressure = hdg
density = 1.03 * 10^3 kg/m^2
P = 50 * 1.03 * 10^3 * 9.8 N/m^2
=
Answered by
1
pressure under water is
Pw = P + ρgh
ρ (density of sea water) = relative density × density of pure water = 1.03×1000 kg/m³
where P = atmospheric pressure = 1 atm = 1×10^5 N/m²
Pw = 1×10^5 + 1.03×1000×9.8×50
= 1×10^5 + 504.7×1000
= 1×10^5 + 5.047×10^5
Pw = 6.047×10^5 N/m² = 6.047atm.
Pw = P + ρgh
ρ (density of sea water) = relative density × density of pure water = 1.03×1000 kg/m³
where P = atmospheric pressure = 1 atm = 1×10^5 N/m²
Pw = 1×10^5 + 1.03×1000×9.8×50
= 1×10^5 + 504.7×1000
= 1×10^5 + 5.047×10^5
Pw = 6.047×10^5 N/m² = 6.047atm.
raghavamritsatyam000:
r u shur that it is correct
this is little confusing
under sea water pressure is pressure applied by atmosphere plus pressure applied by sea water.
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