Question

What is the pressure due to the water at bottom of a 12m deep lake

Answer 1

Pressure at bottom of 12m deep lake = normal atmospheric pressure + ρgh
Here , ρ is density of water , g is Acceleration due to gravity and h is depth.

Given, h = 12m , g = 10m/s² and ρ = 1000 kg/m³
And we know, normal atmospheric pressure = 1atm ≈ 10⁵ N/m²
∴ pressure at bottom of lake = 10⁵ + 1000 × 10 × 12
= 10⁵ + 1.2 × 10⁵
=2.2 × 10⁵ N/m²

Hence, pressure at bottom of lake = 2.2 × 10⁵ N/m² or 2.2 atm

Answer 2

Hello Dear.

Here is the answer---

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Given ⇒

Depth of the Lake(d) = 12 m.

Using the Formula,

 Pressure = ρ × g × d

Where,
ρ = Density of Water    
   = 1000 kg/m³

g = acceleration due to gravity.   
   = 10 m/s²

∴ Pressure = 1000 × 10 × 12                 
                    = 120000 Pa.

Normal Atmospheric Pressure = 1 atm
                                                    = 10⁵ Pa.

Thus, Total Pressure = 120000 + 10⁵
                                  = 120000 + 100000
                                  = 220000
                                  = 2.2 × 10⁵ Pa.


Thus, the Pressure due to the water at the bottom of the Deep lake is 2.2 × 10⁵ Pa.


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Hope it helps.


Have a Good Day.