Question

What is the pressure exerted by 0.801 mol of CO2 in a 13.0 L container at 298 K? Express your answer in atm.

Answer 1

Answer:- 1.51 atm

Solution:- Moles, volume and temperature is given and we are asked to calculate the pressure exerted by carbon dioxide gas.

It's based on an ideal gas law equation, PV = nRT

where, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

$P=\frac{nRT}{V}$

Let's plug in the given values in the equation:

$P=\frac{0.801mol*\frac{0.0821atm.L}{mol.K}*298K}{13.0L}$

P = 1.51 atm

So, the pressure exerted by carbon dioxide gas is 1.51 atm.