Question

What is the pressure on a swimmer 10m below the surface of lake?

Answer 1

p=h*d*g
p=10*1000*10
p=10000pascal

Answer 2

Answer:

HERE,

h = 10m and   ρ = 1000 kg m^-3.

Take g = 10 ms^-2

Here is an Equatiom which is applied :- P = $P_{a}$+ ρgh

Now,

$1.01 \times {10}^{5} pa + 1000 kg {m}^{ - 3} \times 10m {s}^{ - 2} \times10m$

= 2.01 × 10⁵ Pa

= 2atm

This is a 100% increase in pressure from suface level. At a Deoth of 1 km, the increase in pressure is 100 atm ! Submarines are desihned to withstand such enormous pressures.