Question

what is the pressure on a swimmer 10m below the surface of a lake

Answer 1

The total pressure on the swimmer would be the sum of the atmospheric pressure and the pressure due to 10m column of water.

So,

P = Patm + ρgh

Here,

Patm = 10^5 N/m^2

ρ (of water) = 1000 kg/m^3

g = 9.81 m/s^2

h = 10m

Thus, we have

P = 10^5 + (1000x9.81x10)

So, total pressure

P = 1.981 x 10^5 N/m^2

Answer 2

P= $P_{a}$ + pgh

P = 1.01 × 10 ⁵ + 10³×9.8×10

P = 1.99×10⁵ Pa ≈ 2 atm.