Question

What is the pressure on swimmer 20 m.below rhe surface of water

Answer 1

Answer:

3atm

Explanation:Let atmospheric pressure =P  

3

​  

=1.05×10  

5

 Pa

Pressure $$20$m below surface of lake

P=P  

0

​  

+∫gh

=1.05×10  

5

+1000×9.8×20

=3.01×10  

5

 Pa (∫→ water density =1000kg/m  

3

)

=3 atm.

Answer 2

Answer:

Hey mate, Good morning ♡

# Here's ur answer ☆

Explanation:

$pressure \: under \: water \: = d \times g \times h$

$where \: d \: is \: density$

$g \: isgravity$

$and \: h \: is \: depth$

$given \: h = 20m$

$density \: of \: water = 1000kg \: per \: m {}^{3}$

$ad \: gravity \: \: is9.8 \: mper \: s {}^{2}$

$pressure \: under \: water = 20 \times 1000 \times 9.8 = 196000 \: pascal$

Hope it helps u...○●□■☆