Math, asked by Sveta, 1 year ago

what is the principal amount which earns₹132 as compound interest for second year with 10% interest per annum?​

Answers

Answered by venupillai
38

Answer:

The principal is Rs.1200

Step-by-step explanation:

P = principal

R = rate of interest per cent per year

T = number of years

A = final amount

A = P*(1 + R/100)^T

Let A1 denote the amount at the end of the first year.

=> A1 = P*(1 + 10/100)^1

          = P(1 + 0.1)

          = 1.1*P

Let A2 denote the amount at the end of the second year

=> A2 = P*(1 + 10/100)^2

          = P*(1 + 0.1)^2

          = P*(1.1)^2

          = 1.21*P

Clearly, the compound interest (CI) earned DURING the second year will the difference between A2 and A1

CI for second year = A2 - A1

=> 132 = A2 - A1

=> 1.21*P - 1.1*P = 132

=> 0.11*P = 132

=> P = 132/0.11

       = 1200

The required principal amount is Rs.1,200

Answered by deepanrajgc
3

Answer:

1200

Step-by-step explanation:

1200+10% = 1200+120=1320 ( first year)

10% of 1320 is 132 which is given in the question

So, 1200

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