Math, asked by utpal161, 9 months ago

What is the principal argument of (−1−i) where i=√−1?

Answers

Answered by ashauthiras

2

Answer:

So principal value is -π+@

Where @is tan inverse -1/-1=1 =1/4

So argument =-π+π/4=-3π/4

Step-by-step explanation:

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