Question

What is the principal if you earn $300 in interest at a rate of 5% for 6 years?

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Principal=\ 1000}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Simple \: interest(S.I) = \ 300 \\ \\ \tt: \implies Rate\%(r) = 5\% \\ \\ \tt: \implies Time(t) = 6 \: years \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Principal(p) =?$

• According to given question :

$\tt\circ\:Let\:principal\:be\:x \\\\\bold{As \: we \: know \: that} \\ \tt: \implies S.I= \frac{p \times r \times t}{100} \\ \\ \tt: \implies 300 = \frac{x \times 5 \times 6}{100} \\ \\ \tt: \implies 300 \times 100 = 30 \times x \\ \\ \tt: \implies x = \frac{30000}{30} \\ \\ \green{\tt: \implies x = \ 1000} \\ \\ \green{\tt \therefore Principal \: is \:\ 1000} \\ \\ \bold{ \blue{Some \: related \: formula}} \\ \orange{ \tt \circ \: A =p(1 + \frac{r}{100} )^{t} } \\ \\ \orange{ \tt \circ \: A=p(1 + \frac{ \frac{r}{2} }{100} )^{2t} } \\ \\ \orange{ \tt \circ \: A =p(1 + \frac{ \frac{r}{4} }{100} )^{4t} }$

Answer 2

Step-by-step explanation:

Given :

⟹Simpleinterest(S.I)=$300

⟹Rate%( r)=5%

⟹Time(t)=6years

ToFind:

⟹Principal(p)=?

• According to given question :

∘Let principal be x

As we know that,

S.I = p×r×t /100

300 = x × 5 × 6 /100

300×100 = 30 x

x = 30000/30

x = 1000

Principal is $1000