Question

What is the principal quantum no. of H-atom Orbital if the electron energy is -3.4 eV ? also report the angular momentum of electron

Answer 1

Energy = -13.6×Z/n^2

-3.4= 13.6×Z^2/n^2

n^2 = 13.6/3.4

n^2=4

n=2

Angular momentum is nh/2$\pi$

So angular momentum is h/$\pi$