What is the principal value of log(i^1/4)
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i
log(i+1)
ilog(i+1)
?
I tried this way...
log(i+1)log(i)=[log
2
–
√
+i(2nπ+
π
4
)]
∗i(2nπ+
π
2
)
log(i+1)log(i)=[log2+i(2nπ+π4)]∗i(2nπ+π2)
log(i+1)
ilog(i+1)
?
I tried this way...
log(i+1)log(i)=[log
2
–
√
+i(2nπ+
π
4
)]
∗i(2nπ+
π
2
)
log(i+1)log(i)=[log2+i(2nπ+π4)]∗i(2nπ+π2)
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