what is the principle of 10000 in 2 years at 8% per annum compound interest according as the interest is paid yearly and semi annually
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C. I = p[ (1 +I)power n-1]
P = 10000
I= 8/2
=4/100
=0.04
n=4
Now putting the values answer is 1698.5856
P = 10000
I= 8/2
=4/100
=0.04
n=4
Now putting the values answer is 1698.5856
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