What is the probability for a pair of dice to show a sum of 5 or 10?
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Answered by
2
The total number of outcomes, n(s) =36f
Number of favourable outcomes, n(A)=(1,4)(4,1)(2,3)(3,2)(5,5)(4,6)(6,4)
n(A)=7
Probability of an event, P(A)=n(A)/n(s)
=7/36
Therefore the answer is 7/36
Number of favourable outcomes, n(A)=(1,4)(4,1)(2,3)(3,2)(5,5)(4,6)(6,4)
n(A)=7
Probability of an event, P(A)=n(A)/n(s)
=7/36
Therefore the answer is 7/36
Answered by
1
Total number of possibility is 36 as their are two dices.
Favorable condition possiblity of dices to show sum of 5 or 10 = {(1,4),(2,3),(3,2),(4,1),(4,6),(5,5)(6,4)} = 7 .
Therefore favorable condition probability of dices to show sum of 5 or 10 = 7/36.
Hope it helps.
Favorable condition possiblity of dices to show sum of 5 or 10 = {(1,4),(2,3),(3,2),(4,1),(4,6),(5,5)(6,4)} = 7 .
Therefore favorable condition probability of dices to show sum of 5 or 10 = 7/36.
Hope it helps.
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