What is the probability of
1) a card of spade or an ace
2) neither a jack nor a king
3) either a queen or a king
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Answered by
1
total=52
1. spades=13
aces=4
p(AS)=13+4/52
=17/52
2. jacks=4
kings=4
p(Njk)=52-4+4/52
=44/52
=11/13
3.kings=4
queens=4
p(KQ)=4+4/52
=8/52
=2/13
1. spades=13
aces=4
p(AS)=13+4/52
=17/52
2. jacks=4
kings=4
p(Njk)=52-4+4/52
=44/52
=11/13
3.kings=4
queens=4
p(KQ)=4+4/52
=8/52
=2/13
426ri543:
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Answered by
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total no of cards in deck = 52
total no of outcomes = 52
(i) no of spades = 13
no of ace = 4
no of ace of spade = 1
no of favourable outcomes = 13 + 4 - 1 = 16
so required probability = 16/52 = 4/13
(iii) no of kings = 4
no of queens = 4
no of favourable outcomes = 4 + 4 = 8
so required probability = 8/32 = 2/13
total no of outcomes = 52
(i) no of spades = 13
no of ace = 4
no of ace of spade = 1
no of favourable outcomes = 13 + 4 - 1 = 16
so required probability = 16/52 = 4/13
(iii) no of kings = 4
no of queens = 4
no of favourable outcomes = 4 + 4 = 8
so required probability = 8/32 = 2/13
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