Math, asked by tarsemsinghtarsemsin, 8 months ago

What is the probability of 4 coming on one side of dice (¡)1/6(¡¡)2/6 (¡¡¡)3/6 (¡v)4/6​

Answers

Answered by stejendra98
1

Answer:

(i)\frac{1}{6}

Step-by-step explanation:

We know

on a die

The total no. of outcomes = 6

No of possib;e outcomes

Now

P(E) = \frac{No of possible outcomes}{Total no of outcomes}

P( come 4) = \frac{No of times 4 is there}{Total No on die}

                 =  \frac{1}{6}          Ans'

Hope it is helpful

Pls mark it as brainliest

Answered by goonj07
1

Step-by-step explanation:

total (p)= 6

p of coming 4

p= 1/6

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