What is the probability of 53 Mondays and Tuesdays in a leap year.
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Answer:
A leap year has 366 days (52 weeks + 2 days)
That two days may be (sun, mon) (mon, tue) (tue, wed) (wed, thurs) (thurs, fri) (fri, sat) (sat, sun)
∴ n(S) = 7
Number of events for the occurrence of 53 Tuesdays and 53 Mondays, n(E) = 1
n(E)/n(S) = 1/7
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Step-by-step explanation:
Hence, the probability that a leap year will contain 53 Mondays and 53 Tuesdays =n(S)n(E)=71. Was this answer helpful?
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