what is the probability of a leap year to have at least 52 wednesdays?
Answers
Answered by
0
Answer:
0.71
Step-by-step explanation:
Finding the complement of events A to have two odd days not to be {Tuesday & Wednesday}, {Wednesday & Thursday}
= 1 - P(A)
= 1 - 0.29
P(A’) = 0.71
0.71 is probability for 52 Wednesdays in a leap year.
Answered by
0
Answer:
100%
Step-by-step explanation:
Every year has 52 weeks hence 52 Wednesdays
So every year including a leap year has 52 Wednesdays
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