Question

What is the probability of a non leap year having 53 mondays

Answer 1

The probability for a non-leap year i.e 365 days
52 weeks = 364 days  
So the other one day may be Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday

Probability = favorable outcomes/all possible outcomes = 1/7

Answer 2

The probability of a non leap year having 53 Mondays is 1/7

Given:

• Non leap Year

To Find:

• probability of a non leap year having 53 Mondays

Solution:

• Probability of an event  = n(E)/n(S)  
• n(E) = number of possible outcome of event
• n(S) = number of possible sample space outcome
• P(E) + P('not E') = 1
• 7 Days in a week

Non-Leap Year

• Also Called Standard Year
• 365 Days is a non leap year

Leap Year

• Generally comes Every 4 Years
• 366 days in a leap year
• Year Divided by 4 are leap years
• Centaury years Divided by 400 are leap years

Step 1:

Divide 365 Days in Completer weeks and remaining days

365 = 52 x 7  + 1

Hence there will be 52 Days for Each Day of the week.

Step 2:

Find probability of remaining one day to be Monday to get 53 Mondays

P = One possible Monday / Total 7 days in a week

P = 1/7

The probability of a non leap year having 53 Mondays is 1/7

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