Question

What is the probability of arranging the letters of the word CHEMISTRY such that arrangements start with C and end with Y ?

Answer 1

Hi there!
Here's the answer:

•°•°•°•°•°<><><<><>><><>°•°•°•°•°•

CHEMISTRY

Without any restrictions:
Since all letters in the word "CHEMISTRY" are distinct then the no. of arrangements is 9!.

C_______Y
(1)_______(1)

C must occur at the 1st place:
C is fixed at the third place,
=> only 1 way
and
Y must occur at the last.
Y is fixed at last place
=> only 1 way

Remaining letters= H, E, M, I, S, T, R.
No. of remaining leters = 7
other 7 distinct letters can be arranged in 7! ways.

Required probability = (7!/9!) = 1/(9×8) = 1/72

•°•°•°•°•°<><><<><>><><>°•°•°•°•°•

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:)
Hope it helps

Answer 2

Answer:

Therefore, the probability of arranging the letters of the word $CHEMISTRY$ such that arrangements start with $C$ and end with $Y$ is $1.$

Step-by-step explanation:

Given:

The word $CHEMISTRY$ such that arrangements start with $C$and end with $Y.$

To find the probability of arranging the letters of the word CHEMISTRY such that arrangements start with C and end with Y.

Step 1

If we are arranging the term $CHEMISTRY$ such that the arrangements begin with  $C$ and finish with $Y$ there exists only one approach.

Step 2

Probability of arranging the letters of the term  $CHEMISTRY$ such that the arrangements start with  $C$ and finish with

$\mathrm{Y}=\frac{1}{1}=1$

Probability of arranging the letters of the term  $CHEMISTRY$ such that the arrangements start with $C$ and finish with $Y$exists $1.$

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