What is the probability of being dealt a full house, aces over king?
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(a) The number of ways of dealing aces over kings would be. But the total number of ways of choosing 5 cards would be.
(a)A full house has three cards of one kind and two of another, so think about it like this: first you choose a type of card (13 choices), then you choose three out of four of those cards, then you choose a second type of card, and finally you choose two of those four cards. Thus you have (131)(43)(121)(42) possible full house hands. So the probability is then
(131)(43)(121)(42)(525)=(13)(4)(12)(6)2598960=37442598960≈0.00144
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Answer:
(131)(43)(121)(42)(525)=(13)(4)(12)(6)2598960=37442598960≈0.00144
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