what is the probability of coming of a prime number an throwing of a dice?
Answers
Step-by-step explanation:
When throwing a single die, there are six (6) possibilities or outcomes: 1, 2, 3, 4, 5, or 6.
On a single die, there are the three (3) prime numbers or successful outcomes: 2, 3, and 5.
Therefore, ...
The probability of getting a number that is prime with a single roll of the die = Total number of successful outcomes/Total number of possibilities
= Total number of prime numbers/Total number of possibilities
= 3/6
= 1/2
= .50
= 50/100
= 50%
Therefore, there is a 50% chance that a person will get a prime number (2, 3, or 5) with a single roll of a die, that is, with a single roll of a die, there is an equal chance that you'll either get a prime number (2, 3, or 5) or that you won't get a prime number (1, 4, or 6), i.e., 50-50.
Answer:
We find this number by multiplying 6 x 6. The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12 (E)
Step-by-step explanation: