Question

What is the probability of drawing a white ball from a bag containing 3 black balls and 4 white balls?

Answer 1

Answer:

3 white balls are in the faviour of event while 4 black balls are not in the faviour.

Probability = favioural cases of event / total cases.

Here event is drawing the ball from bag.

Favioural cases of event will be 3.

Total cases are 3 + 4 = 7.

So, probability will be 3/7.

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Answer 2

Answer:

$\frac{4}{7}$

Explanation:

Step : 1Finding the likelihood of selecting balls and randomly selecting white and black balls from each bag are the first steps in solving the problem. Then, using the specified criteria, we determine all feasible ways to remove precisely four white balls from the bags. The requisite probability is then calculated using the probabilities we have already received.

Step : 2Calculate the likelihood of drawing a white ball.

Here, four white balls are the favourable event.

The unfortunate occurrence is three black balls.

There are seven balls in all.

Step : 3So, the likelihood of selecting a white ball from a bag

$\begin{aligned}& P(W)=\frac{\text { No. of white balls in the bag }}{\text { Total no of balls in the bag }} \\\Rightarrow & P(W)=\frac{4}{7}\end{aligned}$

In light of this, the likelihood of pulling a white ball from a bag is $\frac{4}{7}$

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