Question

What is the probability of getting 5. Monday's in February in a non-leap year ?​

Answer 1

Answer:

A leap year has 29 days in February,

So we have 4weeks and a day,which can be any of the week day i.e mon,Tue,wed,thu or whatever.

We have 4 Mondays in 4 weeks and that remaining day should be Monday for having 5 Mondays therefore the probability of that day being monday is 1/7

Answer 2

SOLUTION

TO DETERMINE

The probability of getting 5 Mondays in February in a non leap year

EVALUATION

A non leap year = 365 days

In a non leap year the month of February has 28 days

So total number of possible outcomes = 28

Let E be the event that of getting 5 Mondays in February in a non leap year

28 days = 4 weeks

Each week consists of :

Monday , Tuesday , Wednesday , Thursday , Friday , Saturday , Sunday

So in each week there is only one Monday

So total number of Monday in the month = 4

So there is no chance to have 5 Mondays in February in a non leap year

So total number of possible outcomes for the event E = 0

Hence the required probability

= P(E)

$\sf = \dfrac{0}{28}$

= 0

Also the result can be obtained in another way

Since there is no chance to have 5 Mondays in February in a non leap year

So E is an impossible event

We know that the probability of an impossible event is zero

Hence the required probability = 0

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