what is the probability of getting 5 Sunday's in month of February in a leap year?
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Answered by
0
probability = favourable outcomes/total outcomes
February month contain 28 days
so,P=28/5
=5.6
February month contain 28 days
so,P=28/5
=5.6
MalavDoshi:
noo
dear it's a leap year
hii
because it has only one day
2-1 dates for that which it is leap year
ok
Answered by
14
The month of February in a regular month has 28 days, making it impossible to have 5 Sundays. 28 days make up exactly 4 weeks and therefore only for 4 Sundays.
The month of February in a leap year has 29 days, making it possible that the 29th day is on a Sunday, therefore making it 5 Sundays.
Find the total number of possible days that 29th day can fall on:
Total number of possible outcomes = 7
(That is, Mon, Tue, Wed, Thu, Fri, Sat or Sun)
Find the total number of favourable outcome:
Total number of favourable outcome = 1
(That is, Sunday)
Find the probability of having 5 Sundays:
P(5 Sundays) = 1/7
Answer: The probability is 1/7
but 1/7 would be probability of 5th Sunday but I am asking about 5 sumdays
The first 28 days will ensure that there are definitely 4 Sundays. If the month has 5 Sundays depends on the 29th.
If 29th also fall on Sunday, we will have 5 Sundays.
=> That is why the probability of 5 Sundays is dependent on the 5th Sunday only.
If 29th also fall on Sunday, we will have 5 Sundays.
=> That is why the probability of 5 Sundays is dependent on the 5th Sunday only.
Thank you for the brainliest :)
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