Question

What is the probability of getting 5 sundays in December in a calendar year?

Answer 1

In December 31 days are there
1 week=7 days
4*7+3=31
These 3 days which are left will be consecutive so probability of getting 5 Sunday in December is 3/7.

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Answer 2

The probability of getting 5 sundays in December in a calender year is $\frac{3}{7}$

Step-by-step explanation:

We know the formula of probability which is the ratio of no. of outcomes to the total observations.

                                       ⇒ Probability = $\frac{no. of outcomes }{total no. of observations}$

We know that in december month there are total 31 days and in every week there is one sunday. In every 7 days, there is one sunday.

 

So, in 28 days there are 4 sundays in 31 days of December. (  28 is less than 31)

Now, three days has been left  in december. So, 3 is the outcomes and 7 days are under observation.

So,                                  ⇒ Probability = $\frac{3}{7}$