What is the probability of getting 53 Friday's in a leap year
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Answered by
4
Hey
It's 2/7
because a leap year consists of 366 days, i.e., 52 complete weeks and 2 days remain. These 2 days can be any of the following:
(Mon, Tues), (Tues, Wed), (Wed, Thur), (Thur, Fri), (Fri, Sat), (Sat, Sun)
Thus, total number of cases = 7
Number of cases in which we get a Friday = 2
∴Probability of getting 53 Fridays in a leap year = 2/7
Hope this helps you
It's 2/7
because a leap year consists of 366 days, i.e., 52 complete weeks and 2 days remain. These 2 days can be any of the following:
(Mon, Tues), (Tues, Wed), (Wed, Thur), (Thur, Fri), (Fri, Sat), (Sat, Sun)
Thus, total number of cases = 7
Number of cases in which we get a Friday = 2
∴Probability of getting 53 Fridays in a leap year = 2/7
Hope this helps you
goswamikushal3p3zr4d:
Thanks correct explaination
Answered by
2
2/7 is the answer of this
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