Question

What is the probability of getting 53 Fridays in a leap year?

Answer 1

There are 52 weeks and 2 days in a leap year so there are 52 Fridays in a leap year and last 2 days can be any 2 fays(mon and Tues, Tues and wed........ ) as 2 events out of 7 have 'Friday' so probability is 2/7 clear with it OK bye

Answer 2

A leap year consists of 366 days.

52 weeks + 2 days.

These 2 days can be: (mon,tue),(tue,wed),(wed,thu),(thu,fri),(fri,sat)(sat,sun)(sun,mon)

Thus, the total number of cases = 7.

The number of cases in which we get Friday = 2(Thu, Fri)(Fri, Sat).


Therefore the required probability = 2/7.


Hope this helps!