What is the probability of getting 53 fridays in a leap year?
Answers
Answered by
5
A leap year consist 366 days , that is, 52 complete weeks and two days remain. These 2 days can be any of the following
(mon,tues) (tues,wed) (wed.thu) (thu,fri) (fri.sat) (sat,sun)
Thus, total no. of cases = 7
no. of cases in which we get a friday = 2
therefore, probability of getting 53 fridays in a leap year = 2/7
(mon,tues) (tues,wed) (wed.thu) (thu,fri) (fri.sat) (sat,sun)
Thus, total no. of cases = 7
no. of cases in which we get a friday = 2
therefore, probability of getting 53 fridays in a leap year = 2/7
Similar questions