Question

What is the probability of getting 53 Sundays in a leap year and in a non leap year?

Answer 1

1 in leap year =
$\frac{2}{7}$
2 in non leap year =
$\frac{1}{7}$
=

Answer 2

Answer:

We know that A non-leap year consists of 365 days.

In 365 days, Number of weeks = 52 and 1 day remaining.

For 52 weeks, There will be 52 Sundays.The remaining 1 day can be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, and Saturday.

Out of these 7 total outcomes, the favorable outcomes are 1.

Hence the probability of getting 53 Sundays = 1/7.

Hope this helps!