What is the probability of getting 53 Sundays in a leap year?
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1/7 is the probability
hiramani7080:
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Answered by
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Answer:1/7
Step-by-step explanation: In a leap year there will be 52 weeks and one odd day. We will have to count the probability with the help of the odd day as the the no. of days before this odd day will be the same.
Now the total outcomes for this odd day would be 7 (sunday, monday, tuesday, wednesday, thursday, friday, saturday and sunday).
We have to find the probability of sunday, therefore
P(53rd day as sunday) = 1/7
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