What is the probability of getting 53 Sundays in a non leap year
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number of odd days is 1 day
so it may be
Sunday
Tuesday
Wednesday
Thursday
Friday
Saturday
so there are 7 outcomes
so out of 7 only 1 day is possible
therefore p(e)=1/7
so it may be
Sunday
Tuesday
Wednesday
Thursday
Friday
Saturday
so there are 7 outcomes
so out of 7 only 1 day is possible
therefore p(e)=1/7
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