what is the probability of getting a number from prime numbers
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Oftentimes, math problems will require that you know more than one concept. Sometimes, you’ll have to know the difference between an integer and a number in order to get the question right. Below, I’ve combined prime numbers with probability, two subjects already covered in this blog.
The question below isn’t easy and actually takes a little bit of work. Let’s see if you can crack it.
What is the probability that the sum of two rolled dice will equal a prime number?
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
First let’s list the prime numbers that pertain to this problem.
The pertinent prime numbers are 2, 3, 5, 7, and 11. Notice I stopped at 11. Why? Well, the greatest number you can roll on two six-sided dice is 12.
Next, we have to remember this is a probability question. Therefore, we have to divide the number of total outcomes by the number of desired outcomes. First, let’s find the number of desired outcomes. To do this, we have to make sure that each desired outcome conforms to the problem, i.e. how many different ways can we sum two dice to get a prime.
Let’s start with 2. There is only one way to roll a 2, and that is with a 1 and a 1. Therefore, we have one desired outcome.
What about the number 3? Well, we can get 2,1 and 1,2, or two possible ways.
Mind you, to do this problem you will have to make sure you write down each outcome. Do not try to do this in your head, for you’ll most likely get the problem wrong and induce dizziness.
Next we have the number 5, which we can get by rolling the following combinations:
1,4
4,1
2,3
3,2
The question below isn’t easy and actually takes a little bit of work. Let’s see if you can crack it.
What is the probability that the sum of two rolled dice will equal a prime number?
(A) 1/3
(B) 5/36
(C) 2/9
(D) 13/36
(E) 5/12
First let’s list the prime numbers that pertain to this problem.
The pertinent prime numbers are 2, 3, 5, 7, and 11. Notice I stopped at 11. Why? Well, the greatest number you can roll on two six-sided dice is 12.
Next, we have to remember this is a probability question. Therefore, we have to divide the number of total outcomes by the number of desired outcomes. First, let’s find the number of desired outcomes. To do this, we have to make sure that each desired outcome conforms to the problem, i.e. how many different ways can we sum two dice to get a prime.
Let’s start with 2. There is only one way to roll a 2, and that is with a 1 and a 1. Therefore, we have one desired outcome.
What about the number 3? Well, we can get 2,1 and 1,2, or two possible ways.
Mind you, to do this problem you will have to make sure you write down each outcome. Do not try to do this in your head, for you’ll most likely get the problem wrong and induce dizziness.
Next we have the number 5, which we can get by rolling the following combinations:
1,4
4,1
2,3
3,2
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Step-by-step explanation:
S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100}
n(S) = 100
A = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
n(A) = 25
P(A) = n(A)/n(s)
= 25/100
=1/4
Ans :- The probability of the prime numbers from 1 to 100 is 1/4.
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