what is the probability of getting a number
more than 4 in a single throw of a die.
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Step-by-step explanation:
s={1,2,3,4,5,6}
n(s)=6
let be the event that the probability of getting number more than 4 throw a single die
A={5,6}
n(A)=2
p(A)=n(A)/n(s)
=2/6
=1/3
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