Math, asked by simsup2883, 8 months ago

What is the probability of getting a prime number when the digits are 1 4 9 16 25 and 29

Answers

Answered by yoyoganeshmirdha
0

Answer:

numbers - 1,4,9,16,25,29

prime numbers - 1,29

so, probability of getting prime number = (no. of prime no.) / (total number of numbers)

= 2/6

= 1/3

= 0.3334

Answered by pulakmath007
21

\displaystyle\huge\red{\underline{\underline{Solution}}}

TO DETERMINE

The probability of getting a prime number when the digits are 1, 4, 9, 16, 25, 29

EVALUATION

Here the given numbers are 1, 4, 9, 16, 25, 29

So the number of points = 6

So the total number of possible outcomes = 6

Let A be the event that of GETTING A PRIME NUMBER

Now there is only one prime number 29 among the given numbers

So the number of prime number among the given numbers = 1

So the total number of possible outcomes for the event A is 1

Hence the required probability = P(A) =

 =  \displaystyle \:  \frac{1}{6}

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