what is the probability of getting a sum 9 from two throws of dice
Answers
Answered by
7
Total number of cases = 6*6 = 36
Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4
So probability = 4/36 = 1/9
Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4
So probability = 4/36 = 1/9
Answered by
1
S=<11,12,13,14,15,16,
21,22,23,24,25,26,
31,32,33,34,35,36,
41,42,43,44,45,46,
51,52,53,54,55,56
61,62,63,64,65,66>
E=<36,45,54,63>
I E I =4
P(E)=4/36=1/9
this is the answer of your question
21,22,23,24,25,26,
31,32,33,34,35,36,
41,42,43,44,45,46,
51,52,53,54,55,56
61,62,63,64,65,66>
E=<36,45,54,63>
I E I =4
P(E)=4/36=1/9
this is the answer of your question
Similar questions