What is the probability of getting a sum 9 from two throws of dice
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Favorable outcomes,
={(3,6),(4,5),(5,4),(6,3)}
Total outcomes =36
Required probability = Favorable outcomes/ Total outcomes
= 4/36
=1/9
={(3,6),(4,5),(5,4),(6,3)}
Total outcomes =36
Required probability = Favorable outcomes/ Total outcomes
= 4/36
=1/9
Anonymous:
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