Question

What is the probability of getting a sum of 8 from two throws of a dice.
Give me its simple and very easy solution or explanation.​

Answer 1

Sample space for total number of possible outcomes

{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Total number of outcomes = 36

Favorable outcomes for sum of 8 or getting an even number on both the dices are

(2,6),(3,5),(4,4),(5,3),(6,2),(2,2),(2,4),(4,2),(4,6),(6,4),(6,6)

Number of favorable outcomes = 11

The probability of getting a sum of 8 or getting an even number on both the dices, P(E)=

n(S)

n(E)

​

=

36

11

​

んのｱ乇 ﾉｲ ん乇ﾚｱ ﾘのひ ﾶﾑ尺ズ ﾶ乇 ﾑ丂 乃尺ﾑﾉ刀ﾚﾉ乇丂ｲ....

Answer 2

Answer:

36/11 is the correct answer