what is the probability of getting a sum of 9 from to throws of a dice?
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Number of outcomes = 36
Getting sum as 9 = (3,6),(6,3),(5,4),(4,5)
So required probability = 4/36 = 1/9
Getting sum as 9 = (3,6),(6,3),(5,4),(4,5)
So required probability = 4/36 = 1/9
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