what is the probability of getting almost 2 heads and at least 2 heads if we tossed 3 times a coin
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Step-by-step explanation:
The desired event E is to get at least two heads. E = {HHH, HHT, HTH, THH}. So, n(E) =4. Therefore the probability of getting at least two heads when threecoins are simultaneously tossed = n(E)/n(S) = 4/8 =1/2
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