What is the probability of getting either a doublet or total 4 in a single throw with two dice?
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Step-by-step explanation:
If two dice are thrown simultaneously, the possible outcomes are:
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total outcomes=36
For, doublet i.e. the same number on both the dice:-
(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)
Number of successes=6
Total possible outcomes=36
Therefore, probability of getting doublet=number of successes/total possible outcomes=6/36=1/6
Hence, the answer is 1/6
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